Subtract the polynomials. \( \left(-3 r^{2}+3 r+7\right)-\left(7 r^{2}+5 r-2\right) \) \( \left(-3 r^{2}+3 r+7\right)-\left(7 r^{2}+5 r-2\right)=\square \) (Simplify your answer.)

To subtract the polynomials, you need to distribute the negative sign across the second polynomial and then combine like terms: \[ (-3 r^{2} + 3 r + 7) - (7 r^{2} + 5 r - 2) = -3 r^{2} + 3 r + 7 - 7 r^{2} - 5 r + 2 \] Now, combine the like terms: \[ (-3 r^{2} - 7 r^{2}) + (3 r - 5 r) + (7 + 2) = -10 r^{2} - 2r + 9 \] So, the simplified answer is: \[ -10 r^{2} - 2r + 9 \] Now, let's fill in the square: \[ \left(-3 r^{2}+3 r+7\right)-\left(7 r^{2}+5 r-2\right)= -10 r^{2}-2r+9 \]