Solve for \( z \) \[ 9=-\frac{1}{3} z-7 \]

To solve for \( z \) in the equation \( 9=-\frac{1}{3} z-7 \), we first isolate the term involving \( z \): 1. Add \( 7 \) to both sides: \[ 9 + 7 = -\frac{1}{3} z \] \[ 16 = -\frac{1}{3} z \] 2. Now, to eliminate the negative fraction, multiply both sides by \( -3 \): \[ -3 \times 16 = z \] \[ z = -48 \] Thus, the solution is \( z = -48 \).