Solve the equation \( x^{2}+14 x-32=0 \) by factoring. \[ x=\square \] If there is more than 1 solution, separate the values with a comma.

To solve the equation \( x^{2} + 14x - 32 = 0 \) by factoring, we need to find two numbers that multiply to \(-32\) (the constant term) and add up to \(14\) (the coefficient of the \(x\) term). The numbers \(16\) and \(-2\) fit this requirement since \(16 \times -2 = -32\) and \(16 + (-2) = 14\). Thus, we can write the equation as: \[ (x + 16)(x - 2) = 0 \] Setting each factor to zero gives us the solutions: \[ x + 16 = 0 \quad \Rightarrow \quad x = -16 \] \[ x - 2 = 0 \quad \Rightarrow \quad x = 2 \] So, the solutions are: \[ x = -16, 2 \]