Solve the rational equation: \( \frac{x-8}{x}=\frac{63}{x+8} \)
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Extra Insights
To solve the equation \( \frac{x-8}{x} = \frac{63}{x+8} \), we can start by cross-multiplying to eliminate the fractions. This gives us: \[ (x-8)(x+8) = 63x \] Next, we expand the left-hand side: \[ x^2 - 64 = 63x \] Now, rearranging the equation to set it to zero results in: \[ x^2 - 63x - 64 = 0 \] We can factor this quadratic equation. We are looking for two numbers that multiply to \(-64\) and add to \(-63\). These numbers are \(-64\) and \(1\). Therefore, we can factor the equation as follows: \[ (x - 64)(x + 1) = 0 \] Setting each factor equal to zero gives us the possible solutions: 1. \(x - 64 = 0 \Rightarrow x = 64\) 2. \(x + 1 = 0 \Rightarrow x = -1\) However, we must check for extraneous solutions by substituting back into the original equation. For \(x = 64\): \[ \frac{64-8}{64} = \frac{56}{64} = \frac{7}{8} \] \[ \frac{63}{64+8} = \frac{63}{72} = \frac{7}{8} \] So, \(x = 64\) is valid. For \(x = -1\): \[ \frac{-1-8}{-1} = \frac{-9}{-1} = 9 \] \[ \frac{63}{-1+8} = \frac{63}{7} = 9 \] So, \(x = -1\) is also valid. Thus, the solutions to the equation are: \[ \boxed{64 \text{ and } -1} \]
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