olve the equation \( 20 y^{2}+1 y-12=0 \). Nrite your answers as a list of integers or reduced fractions, with your answers separated by (a) comm =or example, if you get 4 and \( -\frac{2}{3} \) as your answers, then enter \( 4,-2 / 3 \) in the box.

Solve the equation \( 20y^{2}+1y-12=0 \). Solve the quadratic equation by following steps: - step0: Solve by factoring: \(20y^{2}+1\times y-12=0\) - step1: Multiply: \(20y^{2}+y-12=0\) - step2: Factor the expression: \(\left(4y-3\right)\left(5y+4\right)=0\) - step3: Separate into possible cases: \(\begin{align}&4y-3=0\\&5y+4=0\end{align}\) - step4: Solve the equation: \(\begin{align}&y=\frac{3}{4}\\&y=-\frac{4}{5}\end{align}\) - step5: Rewrite: \(y_{1}=-\frac{4}{5},y_{2}=\frac{3}{4}\) The solutions to the equation \(20y^{2}+1y-12=0\) are \(y_{1}=-\frac{4}{5}\) and \(y_{2}=\frac{3}{4}\), which can also be written as \(y_{1}=-0.8\) and \(y_{2}=0.75\).