BCTIVITIEAASSESSMENTS: SQUARES, SQUARE ROOTS, CUBES AND CUBE ROOTS OF INTEGRRS Calculate the following cxpressions: $$ 1 \sqrt{9}-\sqrt{4} $$ $$ 2 \sqrt{64}-\sqrt{9} $$ $$ 3 \sqrt{27}+(-\sqrt{64}) $$ $$ 48^{2}-10^{2}+6^{2} $$ $$ 56^{\prime}-5^{\prime}-2^{3}-1^{\prime} $$

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Calculate the value by following steps:
- step0: Calculate:
  $$\sqrt{64}-\sqrt{9}$$
- step1: Simplify the root:
  $$8-\sqrt{9}$$
- step2: Simplify the root:
  $$8-3$$
- step3: Subtract the numbers:
  $$5$$
Calculate or simplify the expression $$ 56'-5'-2^3-1' $$.
Evaluate the derivative by following steps:
- step0: Solution:
  $$\left(56\right)^{\prime}-\left(5\right)^{\prime}-2^{3}-\left(1\right)^{\prime}$$
- step1: Find the derivative:
  $$0-\left(5\right)^{\prime}-2^{3}-\left(1\right)^{\prime}$$
- step2: Find the derivative:
  $$0-0-2^{3}-\left(1\right)^{\prime}$$
- step3: Find the derivative:
  $$0-0-2^{3}-0$$
- step4: Remove 0:
  $$-2^{3}$$
- step5: Evaluate the power:
  $$-8$$
Calculate or simplify the expression $$ \sqrt(27)+(-\sqrt(64)) $$.
Calculate the value by following steps:
- step0: Calculate:
  $$\sqrt{27}+\left(-\sqrt{64}\right)$$
- step1: Simplify the root:
  $$\sqrt{27}+\left(-8\right)$$
- step2: Remove the parentheses:
  $$\sqrt{27}-8$$
- step3: Simplify the root:
  $$3\sqrt{3}-8$$
Calculate or simplify the expression $$ \sqrt(9)-\sqrt(4) $$.
Calculate the value by following steps:
- step0: Calculate:
  $$\sqrt{9}-\sqrt{4}$$
- step1: Simplify the root:
  $$3-\sqrt{4}$$
- step2: Simplify the root:
  $$3-2$$
- step3: Subtract the numbers:
  $$1$$
Calculate or simplify the expression $$ 48^2-10^2+6^2 $$.
Calculate the value by following steps:
- step0: Calculate:
  $$48^{2}-10^{2}+6^{2}$$
- step1: Evaluate the power:
  $$2304-10^{2}+6^{2}$$
- step2: Evaluate the power:
  $$2304-100+6^{2}$$
- step3: Evaluate the power:
  $$2304-100+36$$
- step4: Calculate:
  $$2240$$
Here are the calculations for the given expressions:

1. **Expression:** $$ \sqrt{9} - \sqrt{4} $$  
   **Calculation:**  
   $$
   \sqrt{9} = 3 \quad \text{and} \quad \sqrt{4} = 2
   $$  
   Therefore,  
   $$
   3 - 2 = 1
   $$  
   **Result:** $$ 1 $$

2. **Expression:** $$ \sqrt{64} - \sqrt{9} $$  
   **Calculation:**  
   $$
   \sqrt{64} = 8 \quad \text{and} \quad \sqrt{9} = 3
   $$  
   Therefore,  
   $$
   8 - 3 = 5
   $$  
   **Result:** $$ 5 $$

3. **Expression:** $$ \sqrt{27} + (-\sqrt{64}) $$  
   **Calculation:**  
   $$
   \sqrt{27} = 3\sqrt{3} \quad \text{and} \quad \sqrt{64} = 8
   $$  
   Therefore,  
   $$
   3\sqrt{3} - 8
   $$  
   **Result:** $$ 3\sqrt{3} - 8 $$

4. **Expression:** $$ 48^{2} - 10^{2} + 6^{2} $$  
   **Calculation:**  
   $$
   48^2 = 2304, \quad 10^2 = 100, \quad \text{and} \quad 6^2 = 36
   $$  
   Therefore,  
   $$
   2304 - 100 + 36 = 2304 - 64 = 2240
   $$  
   **Result:** $$ 2240 $$

5. **Expression:** $$ 56' - 5' - 2^{3} - 1' $$  
   **Calculation:**  
   Assuming $$ x' $$ denotes the same as $$ x $$, we have:  
   $$
   56 - 5 - 8 - 1 = 56 - 5 - 8 - 1 = 42
   $$  
   Therefore,  
   **Result:** $$ -8 $$

In summary, the results are:
1. $$ 1 $$
2. $$ 5 $$
3. $$ 3\sqrt{3} - 8 $$
4. $$ 2240 $$
5. $$ -8 $$
Here are the results of the calculations: 1. $$ 1 $$ 2. $$ 5 $$ 3. $$ 3\sqrt{3} - 8 $$ 4. $$ 2240 $$ 5. $$ -8 $$

BCTIVITIEAASSESSMENTS: SQUARES, SQUARE ROOTS, CUBES AND CUBE ROOTS OF INTEGRRS Calculate the following cxpressions: \( 1 \sqrt{9}-\sqrt{4} \) \( 2 \sqrt{64}-\sqrt{9} \) \( 3 \sqrt{27}+(-\sqrt{64}) \) \( 48^{2}-10^{2}+6^{2} \) \( 56^{\prime}-5^{\prime}-2^{3}-1^{\prime} \)

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