Consider the proportion of "successes" \( \hat{p}=\frac{27}{28} \). (a) In fraction form, what is the proportion of failures, \( (1-\hat{p}) \) ? (b) Choose the correct inequality to compare the two proportions.

1. We start with the given proportion of successes: \[ \hat{p} = \frac{27}{28}. \] The proportion of failures is calculated as: \[ 1 - \hat{p} = 1 - \frac{27}{28}. \] 2. Express \(1\) as a fraction with denominator \(28\): \[ 1 = \frac{28}{28}, \] so: \[ 1 - \frac{27}{28} = \frac{28}{28} - \frac{27}{28} = \frac{1}{28}. \] 3. For part (a), the proportion of failures is: \[ \frac{1}{28}. \] 4. For part (b), we compare the success proportion to the failure proportion: \[ \frac{27}{28} \quad \text{and} \quad \frac{1}{28}. \] Since: \[ \frac{27}{28} > \frac{1}{28}, \] the correct inequality is: \[ \frac{27}{28} > \frac{1}{28}. \]