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6. Quantidade de Matéria Envolvida na Reação Quantos mols de NaOH são necessários para neutralizar completamente \( 0,02 \mathrm{~mol} \) de \( \mathrm{H}_{2} \mathrm{SO}_{4} \) ?

Ask by Chambers Montgomery. in Brazil
Feb 24,2025

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Para neutralizar completamente 0,02 mol de H₂SO₄, são necessários 0,04 mol de NaOH.

Solución

Para a reação de neutralização, a equação balanceada é: H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O Isso significa que 1 mol de H₂SO₄ reage com 2 mols de NaOH. Dado que temos 0,02 mol de H₂SO₄, a quantidade de NaOH necessária é: Quantidade de NaOH = 2 × 0,02 mol = 0,04 mol Portanto, são necessários 0,04 mol de NaOH para neutralizar completamente 0,02 mol de H₂SO₄.

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Para neutralizar completamente \( \mathrm{H}_{2} \mathrm{SO}_{4} \), é necessário considerar que cada mol de ácido sulfúrico reage com dois mols de hidróxido de sódio, \( \mathrm{NaOH} \). Assim, para neutralizar \( 0,02 \, \mathrm{mol} \) de \( \mathrm{H}_{2} \mathrm{SO}_{4} \), você precisaria de: \[ 0,02 \, \mathrm{mol} \times 2 = 0,04 \, \mathrm{mol} \, \mathrm{NaOH} \] Então, são necessários \( 0,04 \, \mathrm{mol} \) de \( \mathrm{NaOH} \) para a neutralização completa. Sabia que essa reação é um clássico exemplo de neutralização em laboratórios de química? Quando o ácido e a base se juntam, forma-se sal e água, liberando calor. É como se a natureza estivesse celebrando a união das moléculas! Manter os elementos na proporção correta é essencial para garantir que tudo reaja perfeitamente, evitando restos indesejados de ácidos ou bases.

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