25. 25.1 Give the equation (formula) that is used to calculate the energy of a photon. 25.1 in terms of \( h \) and \( f \) : 25.2 interms of \( h \), cand \( \lambda \) : \( \qquad \) 25.3 What is the name, value and unit of the prowortionality constant c in the above equations? \( \qquad \) 26. Why will an infrared photon have less e.aetav then ar ultreviolet ohoton? \( \qquad \) \( \qquad \) 27. Why will the photon of red light have less penemation abiity than a gamma ray photon? \( \qquad \)
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Bonus Knowledge
The equation to calculate the energy of a photon in terms of Planck’s constant \( h \) and frequency \( f \) is given by the formula \( E = h \cdot f \). When referring to wavelength \( \lambda \), the equation transforms to \( E = \frac{h \cdot c}{\lambda} \), where \( c \) is the speed of light. The proportionality constant \( c \) is known as the speed of light in a vacuum, and it has a value of approximately \( 3.00 \times 10^8 \) meters per second (m/s). This constant plays a crucial role in various areas of physics, relating the wavelengths and frequencies of electromagnetic radiation to their energy. Infrared photons have less energy than ultraviolet photons because they have longer wavelengths and lower frequencies. Energy is directly proportional to frequency, meaning that as the frequency decreases (like in the infrared), so does the energy of the photon. This is why infrared radiation is often felt as heat rather than visible light. Red light photons have longer wavelengths than gamma ray photons, which significantly affects their penetration ability. Gamma rays have much higher energy and shorter wavelengths, allowing them to penetrate materials more effectively. In contrast, red light interacts more readily with matter, resulting in lower penetration. That’s why we can see red light but not gamma rays!
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