Pregunta
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\begin{tabular}{l} Question \\ A deck of cards contains RED cards numbered \( 1,2,3,4,5 \) and BLUE cards numbered 1,2 . Let \( R \) be the event of drawing a \\ red card, \( B \) the event of drawing a blue card, \( E \) the event of drawing an even numbered card, and \( O \) the event of drawing \\ an odd card. \\ Drawing the Red 1 is one outcome of which of the following events? Select all correct answers. \\ Select all that apply: \\ B AND \( O \) \\ \( \square B \) OR \( E \) \\ \( \square B \) OR \( O \) \\ \( \square O^{\prime} \) \\ \( \square E^{\prime} \) \\ \( \square R \) AND \( E \) \\ \hline\end{tabular}

Ask by Long Schofield. in the United States
Feb 27,2025

Solución de inteligencia artificial de Upstudy

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Drawing the Red 1 belongs to the events \( B \) OR \( O \) and \( E^{\prime} \).

Solución

To determine which events the outcome of drawing the Red 1 belongs to, we first need to clarify the definitions of the events: - **Event \( R \)**: Drawing a red card. The red cards are \( 1, 2, 3, 4, 5 \). - **Event \( B \)**: Drawing a blue card. The blue cards are \( 1, 2 \). - **Event \( E \)**: Drawing an even numbered card. The even cards are \( 2, 4 \) (from red) and \( 2 \) (from blue). - **Event \( O \)**: Drawing an odd numbered card. The odd cards are \( 1, 3, 5 \) (from red) and \( 1 \) (from blue). Now, let's analyze the outcome of drawing the Red 1: 1. **\( B \) AND \( O \)**: - Red 1 is not a blue card, so this event does not apply. - **Not applicable**. 2. **\( B \) OR \( E \)**: - Red 1 is not a blue card, but it is not an even card either. - **Not applicable**. 3. **\( B \) OR \( O \)**: - Red 1 is not a blue card, but it is an odd card. - **Applicable**. 4. **\( O^{\prime} \)**: - \( O^{\prime} \) refers to not drawing an odd card. Since Red 1 is an odd card, this event does not apply. - **Not applicable**. 5. **\( E^{\prime} \)**: - \( E^{\prime} \) refers to not drawing an even card. Since Red 1 is not an even card, this event applies. - **Applicable**. 6. **\( R \) AND \( E \)**: - Red 1 is a red card, but it is not an even card. - **Not applicable**. Based on this analysis, the applicable events for drawing the Red 1 are: - \( B \) OR \( O \) - \( E^{\prime} \) Thus, the correct answers are: - \( \square B \) OR \( O \) - \( \square E^{\prime} \)

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Bonus Knowledge

The Red 1 is an odd card, so it will certainly fall under the event of drawing an odd card \( O \). However, it is not a blue card, so it cannot be part of the event \( B \). The events \( E \) (even) and \( O \) (odd) are mutually exclusive, which means drawing Red 1 wouldn't satisfy the even condition. Now, since Red 1 is indeed a red card, it satisfies the criteria for \( R \) (red card). The event \( O' \) (not odd) and \( E' \) (not even) would not apply as Red 1 is specifically odd and not even. Overall, the correct choices would be: - \( R \) AND \( E \) - False (Red 1 is not even) - \( B \) AND \( O \) - False (Red 1 is not blue) - \( B \) OR \( E \) - False (Red 1 is not blue and is not even) - \( B \) OR \( O \) - False (Red 1 is not blue) - \( O' \) - False (because Red 1 is odd) - \( E' \) - True (because Red 1 is not even) So the “drawing the Red 1 is one outcome of” relates to: - \( O \) (odd) - \( R \) (red)

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