What is the result of adding the system of equations? \( \begin{array}{l}2 x+y=4 \\ 3 x-y=6 \\ x=10 \\ x=2 \\ 5 x=10\end{array} \)

Solve the system of equations \( 2x+y=4;3x-y=6;x=10;x=2;5x=10 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}2x+y=4\\3x-y=6\\x=10\\x=2\\5x=10\end{array}\right.\) - step1: Rearrange the terms: \(\left\{ \begin{array}{l}2x+y=4\\3x-y=6\\x=10\\x=2\end{array}\right.\) - step2: Substitute the value of \(x:\) \(\left\{ \begin{array}{l}2\times 10+y=4\\3\times 10-y=6\\10=2\end{array}\right.\) - step3: Simplify: \(\left\{ \begin{array}{l}20+y=4\\30-y=6\\10=2\end{array}\right.\) - step4: Calculate: \(\left\{ \begin{array}{l}x \in \varnothing \\y \in \varnothing \end{array}\right.\) - step5: Rewrite: \((x, y) \in \varnothing\) The system of equations does not have a solution. Therefore, the result of adding the system of equations is that there is no solution.