\( \begin{aligned} 238 \times 35 & =238 \times(30+5) \\ & =(238 \times 30)+(238 \times 5) \\ & =(238 \times 3 \times 10)+(238 \div 2 \times 10) \\ & =(714 \times 10)+(119 \times 10) \\ & =7140+1190 \\ & =8330\end{aligned} \) EXerciseta. Do these multiplications by breaking down one of the numbers as the example above: \( \begin{array}{ll}\text { 1. } 343 \times 25 & \text { 2. } 4001 \times 43 \\ \text { 3. } 453 \times 72 & \text { 4. } 3200 \times 66\end{array} \)

Below are the step‐by‐step solutions using the distributive property, similar to the example shown. 1. Calculate 343 × 25   Break 25 as (20 + 5):   343 × 25 = 343 × (20 + 5)     = (343 × 20) + (343 × 5)   Compute 343 × 20:   343 × 20 = 343 × (2 × 10) = (343 × 2) × 10     343 × 2 = 686, so (686) × 10 = 6860   Compute 343 × 5:   343 × 5 = 1715   Now add the parts:   6860 + 1715 = 8575 2. Calculate 4001 × 43   Break 43 as (40 + 3):   4001 × 43 = 4001 × (40 + 3)     = (4001 × 40) + (4001 × 3)   Compute 4001 × 40:   4001 × 40 = 4001 × (4 × 10) = (4001 × 4) × 10     4001 × 4 = 16004, so (16004) × 10 = 160040   Compute 4001 × 3:   4001 × 3 = 12003   Now add the parts:   160040 + 12003 = 172043 3. Calculate 453 × 72   Break 72 as (70 + 2):   453 × 72 = 453 × (70 + 2)     = (453 × 70) + (453 × 2)   Compute 453 × 70:   453 × 70 = 453 × (7 × 10) = (453 × 7) × 10     453 × 7 = 3171, so (3171) × 10 = 31710   Compute 453 × 2 = 906   Now add the parts:   31710 + 906 = 32616 4. Calculate 3200 × 66   Break 66 as (60 + 6):   3200 × 66 = 3200 × (60 + 6)     = (3200 × 60) + (3200 × 6)   Compute 3200 × 60:   3200 × 60 = 3200 × (6 × 10) = (3200 × 6) × 10     3200 × 6 = 19200, so (19200) × 10 = 192000   Compute 3200 × 6 = 19200   Now add the parts:   192000 + 19200 = 211200 Thus, the answers are: 1. 343 × 25 = 8575 2. 4001 × 43 = 172043 3. 453 × 72 = 32616 4. 3200 × 66 = 211200