Question Use the square roots property to solve the quadratic equation \( w^{2}+6 w+9=121 \). If there are multiple answers, list them separated by a comma, e.g. 1,2 . If there is no solution, enter \( \varnothing \).

First, let's rewrite the equation by moving 121 to the left side: \( w^{2} + 6w + 9 - 121 = 0 \) This simplifies to: \( w^{2} + 6w - 112 = 0 \) Next, we can recognize that the left side can be factored: \( (w + 12)(w - 6) = 0 \) From here, we can set each factor equal to zero: 1. \( w + 12 = 0 \) gives \( w = -12 \) 2. \( w - 6 = 0 \) gives \( w = 6 \) Thus, the solutions to the equation are: -12, 6