\begin{tabular}{l} Write \( \stackrel{\rightharpoonup}{A B} \) with \( A(-9,2) \) and \( B(-1,-6) \) in component \\ form. \\ \begin{tabular}{l}\( \bigcirc\langle 8,8\rangle \) \\ \hline\( \langle-8,-8\rangle \) \\ \hline\( \langle-8,8\rangle \) \\ \hline\( \langle 8,-8\rangle \)\end{tabular} \\ \hline\end{tabular}

To express the vector \( \stackrel{\rightharpoonup}{AB} \) in component form, we can use the formula: \[ \stackrel{\rightharpoonup}{AB} = \langle B_x - A_x, B_y - A_y \rangle \] Here, \( A(-9, 2) \) and \( B(-1, -6) \). Calculating the components: 1. \( B_x - A_x = -1 - (-9) = -1 + 9 = 8 \) 2. \( B_y - A_y = -6 - 2 = -8 \) So, \( \stackrel{\rightharpoonup}{AB} \) in component form is: \[ \langle 8, -8 \rangle \] And looking at the options, \( \langle 8, -8 \rangle \) is the correct answer!