The highway mileage ( mpg ) for a sample of 8 different models of a car company can be found belore. Find the mean, median, mode, and standard deviation. Round to one decimal place as needed. \( 20,23,26,28,29,32,33,33 \) Mean \( =\square \) Median \( =\square \) Mode \( =\square \) Standard Deviation \( = \)

We are given the following data: 20, 23, 26, 28, 29, 32, 33, 33. Step 1. Calculate the Mean:  • Sum of the values = 20 + 23 + 26 + 28 + 29 + 32 + 33 + 33 = 224.  • Mean = 224 ÷ 8 = 28.0. Step 2. Find the Median:  • Since there are 8 (an even number) values, the median is the average of the 4th and 5th numbers.  • The sorted list is already: 20, 23, 26, 28, 29, 32, 33, 33.  • The 4th value is 28 and the 5th value is 29.  • Median = (28 + 29) ÷ 2 = 28.5. Step 3. Identify the Mode:  • The mode is the number that appears most frequently.  • Here, 33 appears twice and all other numbers appear only once.  • Mode = 33. Step 4. Compute the Standard Deviation:  • First, calculate each value’s deviation from the mean and then square it (using mean = 28.0):   20: (20 − 28)² = (−8)² = 64   23: (23 − 28)² = (−5)² = 25   26: (26 − 28)² = (−2)² = 4   28: (28 − 28)² = 0² = 0   29: (29 − 28)² = 1² = 1   32: (32 − 28)² = 4² = 16   33: (33 − 28)² = 5² = 25   33: (33 − 28)² = 5² = 25  • Sum of squared deviations = 64 + 25 + 4 + 0 + 1 + 16 + 25 + 25 = 160.  • Since this is a sample of 8 models, use n − 1 (7) for the sample variance:   Sample variance = 160 ÷ 7 ≈ 22.9  • Standard deviation = √(22.9) ≈ 4.8. Final Answers (rounded to one decimal place):  Mean = 28.0  Median = 28.5  Mode = 33  Standard Deviation = 4.8