1. En lo ciudo de xalapa debido a los trobolos de montenimiento se Pintoró el monumento de la araucaria. Para ello. se reguere de grua con un bazo mecánico que permita Negar hasto la Porte más alto de 10 estructura sin embargo. Por el tipo de suolo del sitio y estructura misma, la guúa no puede acercarse mucho a bsta. La maquina se Coloco en ciorto punto donde el brazo alcanza la Parte mós alto con ángulo de \( 60^{\circ} \), posteriormente avonza 8 metros y el óngulo del brazo toma un valor de \( 80^{\circ} \). Se necesita conocer la contidad de pintura que se requiere Para Pintara que so reaukere para pintar la estructura, por ello. Se necesita saber su altura. Si son 25 litros de Pintura un metro de altura de la escuitura, ¿cuántos litros de Pintura se necesitan Para Pintarla en su totalidad?

Alright, I need to determine the amount of paint required to paint the entire structure based on the given information. Let's break down the problem step by step to ensure accuracy. First, let's understand the scenario: 1. **Location and Maintenance Issues**: The monument of the Araucaria is located in Xalapa, and due to maintenance troubles, a painter is using a crane with a mechanical base to reach the highest part of the structure. The crane can extend up to 10 meters, but due to the type of soil and the structure's design, the crane cannot approach too closely to the base. 2. **Crane Positioning**: - **Initial Position**: The crane is placed at a point where the arm reaches the highest part with an angle of \(60^\circ\). - **Movement**: The crane then moves 8 meters, and the angle of the arm changes to \(80^\circ\). 3. **Painting Requirements**: - It's given that 25 liters of paint are needed for every meter of height of the structure. - The goal is to find out the total amount of paint required to paint the entire structure. **Objective**: Calculate the total height of the structure and then determine the total amount of paint needed based on the given rate of 25 liters per meter. **Approach**: To find the height of the structure, I'll need to analyze the crane's movement and the angles involved. Since the crane moves 8 meters and changes its angle from \(60^\circ\) to \(80^\circ\), I can model this scenario using trigonometry. **Step 1: Understanding the Crane's Movement** - **Initial Position**: The crane's arm reaches the highest point at an angle of \(60^\circ\). This implies that the vertical height (\(h_1\)) can be calculated using the sine function: \[ h_1 = \text{Length of the arm} \times \sin(60^\circ) \] However, the length of the arm isn't directly provided. Instead, the crane can extend up to 10 meters, but it's not clear if this is the length of the arm or the maximum reach. For the sake of this problem, I'll assume that the crane's arm length is 10 meters. So, \[ h_1 = 10 \times \sin(60^\circ) = 10 \times \frac{\sqrt{3}}{2} \approx 8.66 \text{ meters} \] - **After Movement**: The crane moves 8 meters, and the angle changes to \(80^\circ\). This movement likely involves the crane moving horizontally, but the exact mechanism isn't specified. For simplicity, I'll assume that the crane's arm length remains constant at 10 meters, and the change in angle affects the vertical height. Using the new angle: \[ h_2 = 10 \times \sin(80^\circ) \approx 10 \times 0.9848 \approx 9.848 \text{ meters} \] **Step 2: Calculating the Total Height** The total height (\(H\)) of the structure can be considered as the sum of the heights at both positions, assuming the crane's movement adds to the vertical reach: \[ H = h_1 + h_2 = 8.66 + 9.848 \approx 18.508 \text{ meters} \] **Step 3: Determining the Total Paint Required** Given that 25 liters of paint are needed for every meter of height: \[ \text{Total Paint} = H \times 25 = 18.508 \times 25 \approx 462.7 \text{ liters} \] **Considerations and Assumptions**: - **Crane Arm Length**: I assumed the crane's arm length is 10 meters. If the actual arm length is different, the calculations will change accordingly. - **Movement Mechanism**: The problem states that the crane moves 8 meters and changes the angle, but the exact mechanism of how this affects the vertical height isn't clear. For this calculation, I assumed that the arm length remains constant, and the angle change directly affects the vertical reach. - **Paint Application Rate**: The rate of 25 liters per meter is given, but it's essential to ensure that this rate accounts for the entire surface area to be painted, including any overlaps or additional layers if required. **Potential Errors and Corrections**: - **Angle Misinterpretation**: If the angles represent the angle between the arm and the ground rather than the angle of elevation, the calculations would differ. Clarifying the angle's reference point is crucial. - **Crane Movement Impact**: If the crane's movement affects the arm's length or the angle differently, the height calculations would need to be adjusted accordingly. - **Paint Application Efficiency**: The 25 liters per meter rate assumes uniform application and no waste. In real-world scenarios, factors like paint viscosity, application method, and surface texture can affect the actual amount needed. **Conclusion**: Based on the given information and the assumptions made, approximately 462.7 liters of paint are required to paint the entire structure. However, it's advisable to verify the crane's specifications and the actual movement mechanism to ensure the accuracy of these calculations.