\( 1 \leftarrow \) A date in the month of April is chosen at random. Find the probability of the event of the date's being each of the following. \( \begin{array}{ll}\text { a. April } 3 & \text { b. April } 31\end{array} \) c. Before April 14 a. The probability of the event of the date's being April 3 is (Type an integer or a simplified fraction.)

The total number of days in April is 30. Therefore, the probability of randomly selecting April 3, which is just one specific date, is \( \frac{1}{30} \). For part b, April only has 30 days, so the event of choosing April 31 is impossible. As such, the probability of the event of the date’s being April 31 is \( 0 \). For part c, to find the probability of selecting a date before April 14, we count the days from April 1 to April 13, which is 13 days. Therefore, the probability is \( \frac{13}{30} \).