A toy truck weighing 42 N is placed on a rough, flat surface and a rope is tied to it. The tension in the rope can be increased to \( 20,6 \mathrm{~N} \) before the truck starts to slide. A force of \( 15,4 \mathrm{~N} \) will keep the truck moving at constant speed once it has been set in motion. Determine the coefficients of static and kinetic friction.

We are given that the toy truck weighs 42 N. When the truck is at rest, the maximum tension that can be applied via the rope before it begins to slide is 20.6 N. This maximum tension is balanced by the maximum static friction force. Once the truck is in motion, a force of 15.4 N is sufficient to keep it moving at constant speed; this applied force equals the kinetic friction force because an object moving at constant speed has zero net force. Assuming the rope is horizontal, the normal force on the truck is simply equal to its weight, 42 N. Step 1. Coefficient of Static Friction (μₛ): The maximum static friction force is given by:   fₛ(max) = μₛ × N Since fₛ(max) = 20.6 N and N = 42 N:   μₛ = 20.6 N / 42 N ≈ 0.49 Step 2. Coefficient of Kinetic Friction (μₖ): Similarly, when moving at constant speed, the friction force (kinetic) is:   fₖ = μₖ × N Given fₖ = 15.4 N and N = 42 N:   μₖ = 15.4 N / 42 N ≈ 0.37 Thus, the coefficients are:   Coefficient of static friction (μₛ) ≈ 0.49   Coefficient of kinetic friction (μₖ) ≈ 0.37