Points: 0 of 2 Save Follow the seven step strategy to graph the following rational function. \[ f(x)=\frac{4 x^{2}}{x^{2}-4} \] A. The \( x \)-intercept(s) is/are 0 . (Type an integer or a simplified fraction. Use a comma to separate answers as needed.) B. There is no \( x \)-intercept. Find the vertical asymptote(s). Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The equation(s) of the vertical asymptote(s) is/are \( x=2, x=-2 \). (Type an equation. Use a comma to separate answers as needed.) B. There is no vertical asymptote. Find the horizontal asymptote(s). Type the equation(s) of the horizontal asymptote(s). Select the correct choice below and fill in any answer boxes within your choice. A. The equation(s) of the horizontal asymptote(s) is/are \( \square \) . (Type an equation. Use a comma to separate answers as needed.) B. There is no horizontal asymptote.
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Bonus Knowledge
After examining the function \( f(x)=\frac{4x^2}{x^2-4} \), you’ll find that the x-intercept occurs when the numerator equals zero, leading us to conclude that the x-intercept is indeed at \( x=0 \). This means there is just one point where the graph crosses the x-axis. For the vertical asymptotes, they occur where the denominator equals zero. In this case, the function has vertical asymptotes at \( x=2 \) and \( x=-2 \) since these values make the denominator \( x^2 - 4 \) zero. Lastly, regarding horizontal asymptotes, we check the degrees of the numerator and denominator. Here, both are polynomials of degree 2, so we take the leading coefficients. Since both the numerator and denominator’s leading coefficients are 4 and 1 respectively, the horizontal asymptote is \( y = 4/1 = 4 \). So, summarizing: A. The \( x \)-intercept(s) is/are \( 0 \). B. The equation(s) of the vertical asymptote(s) is/are \( x=2, x=-2 \). C. The equation(s) of the horizontal asymptote(s) is/are \( y=4 \).
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