Solve the inequality \( a+10 \geq \frac{12}{7} \), and write the solution in interval notation.

To solve the inequality \( a+10 \geq \frac{12}{7} \), we start by isolating \( a \). We can do this by subtracting 10 from both sides: \[ a \geq \frac{12}{7} - 10 \] Next, we convert 10 into a fraction with a denominator of 7: \[ 10 = \frac{70}{7} \] Now we can rewrite the right side of the inequality: \[ \frac{12}{7} - \frac{70}{7} = \frac{12 - 70}{7} = \frac{-58}{7} \] This gives us the inequality: \[ a \geq \frac{-58}{7} \] In interval notation, this is expressed as: \[ \left[ \frac{-58}{7}, \infty \right) \]