\( 3 b ^ { 2 } - 27 + b ^ { 2 } y + 3 y \)

Let’s simplify the expression \( 3b^2 - 27 + b^2y + 3y \). First, we can group the terms that have \( b^2 \): \[ (3b^2 + b^2y) + (3y - 27) \] Now, factor out \( b^2 \) from the first group: \[ b^2(3 + y) + (3y - 27) \] You can also notice that \( 3y - 27 \) can be factored out by taking \( 3 \) out: \[ b^2(3 + y) + 3(y - 9) \] So the final simplified form of the expression is: \[ b^2(3 + y) + 3(y - 9) \] This makes it easier to analyze or plug in values for \( b \) and \( y \) in any calculations or problems you might be facing!