Pregunta
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Rafael plants vegetables in \( \frac{4}{5} \) of his garden. The total area of his garden is 15 square meters. What is the area or his garden that will nor be planted with vegetables? Bea has this length of ribbon. She will use \( \frac{5}{6} \) of it to wrap A present. How many inches of ribbon will she use? Timora goes to school for 7 hours each day She spends \( \frac{f}{6} \) of each day in dass. How many hours does she spend in class each school doy?

Ask by Turner Osborne. in the United States
Feb 27,2025

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- **Rafael's Garden:** 3 square meters not planted with vegetables. - **Bea's Ribbon:** \( \frac{5}{6} \) of the total ribbon length used. - **Timora's School Day:** \( \frac{f}{6} \times 7 \) hours spent in class.

Solución

Let's solve each part of the problem step by step. ### Part 1: Rafael's Garden 1. **Known Conditions:** - Total area of the garden = 15 square meters - Area planted with vegetables = \( \frac{4}{5} \) of the total area 2. **Calculate the area planted with vegetables:** \[ \text{Area planted} = \frac{4}{5} \times 15 \] 3. **Calculate the area not planted with vegetables:** \[ \text{Area not planted} = \text{Total area} - \text{Area planted} \] Let's perform the calculations for Rafael's garden. ### Part 2: Bea's Ribbon 1. **Known Conditions:** - Total length of ribbon = unknown (let's denote it as \( r \)) - Length used to wrap a present = \( \frac{5}{6} \) of the total length 2. **Calculate the length of ribbon used:** \[ \text{Length used} = \frac{5}{6} \times r \] Since we don't have the total length of the ribbon, we cannot calculate a specific number. However, we can express the length used in terms of \( r \). ### Part 3: Timora's School Day 1. **Known Conditions:** - Total hours in school = 7 hours - Time spent in class = \( \frac{f}{6} \) of the total hours 2. **Calculate the time spent in class:** \[ \text{Time in class} = \frac{f}{6} \times 7 \] Again, we need to know the value of \( f \) to calculate a specific number. However, we can express the time spent in class in terms of \( f \). Now, let's perform the calculations for Rafael's garden. ### Calculating Rafael's Garden Area \[ \text{Area planted} = \frac{4}{5} \times 15 = 12 \text{ square meters} \] \[ \text{Area not planted} = 15 - 12 = 3 \text{ square meters} \] Now, let's summarize the results: 1. **Rafael's Garden:** - Area not planted with vegetables: \( 3 \) square meters 2. **Bea's Ribbon:** - Length of ribbon used: \( \frac{5}{6} \times r \) (where \( r \) is the total length of the ribbon) 3. **Timora's School Day:** - Time spent in class: \( \frac{f}{6} \times 7 \) (where \( f \) is the total hours in class) If you have specific values for \( r \) and \( f \), please provide them for further calculations.

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Bonus Knowledge

Rafael has a garden area of 15 square meters, and he uses \( \frac{4}{5} \) of it for vegetables. To find the area he won't plant, we subtract the planted area (which is \( \frac{4}{5} \times 15 = 12 \) square meters) from the total area (15 square meters). Thus, the area left unplanted is \( 15 - 12 = 3 \) square meters. For Bea's ribbon, she will use \( \frac{5}{6} \) of her ribbon. If we assume she has a total length of 36 inches, then she will use \( \frac{5}{6} \times 36 = 30 \) inches of ribbon for wrapping the present. That leaves her with 6 inches for any other magical surprises she might have in mind! As for Timora, if she goes to school for 7 hours a day and spends \( \frac{f}{6} \) in class, then we can calculate her class time with \( \frac{1}{6} \) of 7 hours. Thus, \( 7 \times \frac{1}{6} = \frac{7}{6} = 1 \frac{1}{6} \) hours, or 1 hour and 10 minutes, spent learning in class every day. Voila! All clear and mathematically fabulous!

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