Determine the total current, $$ l_{\mathrm{T}} $$, for the circuit, given: $$ E_{\mathrm{T}}=152 \mathrm{~V}, E_{1}=8 \mathrm{~V}, E_{3}=25 \mathrm{~V} $$, and $$ R_{2}=451 \Omega $$ (Round the FINAL answer to two decimal places.)

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We start by assuming the circuit has a series loop in which the net electromotive force (EMF) across resistor R₂ is given by subtracting the smaller voltage sources from the total voltage. In other words, the effective voltage driving the current through R₂ is

E_effective = E_T – E₁ – E₃.

Plug in the values:

E_effective = 152 V – 8 V – 25 V = 119 V.

Then using Ohm’s law, the total current (l_T) is

l_T = E_effective / R₂ = 119 V / 451 Ω.

Now, calculate the current:

l_T ≈ 0.26386 A.

Rounding to two decimal places, the total current is approximately

l_T ≈ 0.26 A.
The total current $$ l_{\mathrm{T}} $$ is approximately 0.26 A.

Determine the total current, \( l_{\mathrm{T}} \), for the circuit, given: \( E_{\mathrm{T}}=152 \mathrm{~V}, E_{1}=8 \mathrm{~V}, E_{3}=25 \mathrm{~V} \), and \( R_{2}=451 \Omega \) (Round the FINAL answer to two decimal places.)

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