Question 8 of 8, Step 1 of 1 Completely factor the expression by grouping, if possible. Correct $$ 8 b a-1-6 b^{2}-b $$

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To factor the expression $$ 8ba - 1 - 6b^2 - b $$ by grouping, we can follow these steps:

1. **Rearrange the expression**: Group the terms in a way that makes it easier to factor. We can rearrange it as:
   $$
   (8ba - 6b^2) + (-b - 1)
   $$

2. **Factor out common factors from each group**:
   - From the first group $$ 8ba - 6b^2 $$, we can factor out $$ 2b $$:
     $$
     2b(4a - 3b)
     $$
   - From the second group $$ -b - 1 $$, we can factor out $$-1$$:
     $$
     -1(b + 1)
     $$

3. **Combine the factored groups**:
   Now we have:
   $$
   2b(4a - 3b) - 1(b + 1)
   $$

4. **Check for common factors**: 
   The expression does not have a common factor between the two groups, so we cannot factor it further.

Thus, the expression $$ 8ba - 1 - 6b^2 - b $$ can be factored as:
$$
2b(4a - 3b) - (b + 1)
$$

However, it appears that this expression does not factor neatly into a product of simpler polynomials. Therefore, the final factored form is:
$$
2b(4a - 3b) - (b + 1)
$$

If you need further assistance or a different approach, please let me know!
The expression $$ 8ba - 1 - 6b^2 - b $$ can be factored as $$ 2b(4a - 3b) - (b + 1) $$.

Question 8 of 8, Step 1 of 1 Completely factor the expression by grouping, if possible. Correct \( 8 b a-1-6 b^{2}-b \)

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