Pregunta
5 from Unit 6, Lesson 11 Find two different ways to rewrite \( 3 x y+6 y z \) using the distributive property.
Ask by Simpson Haynes. in the United States
Feb 25,2025
Solución de inteligencia artificial de Upstudy
Respuesta verificada por el tutor
Responder
There are two ways to rewrite \( 3xy + 6yz \) using the distributive property:
1. **Method 1**: Factor out \( 3y \):
\[
3y(x + 2z)
\]
2. **Method 2**: Group and factor out \( 3y \):
\[
3y(x + 2z)
\]
Both methods result in the same factored form.
Solución
To rewrite the expression \( 3xy + 6yz \) using the distributive property, we can approach it in two different ways.
### Method 1: Factoring out the common factor
1. **Identify the common factor**: In the expression \( 3xy + 6yz \), we can see that \( 3y \) is a common factor.
2. **Factor out the common factor**: We can factor \( 3y \) out of both terms:
\[
3xy + 6yz = 3y(x + 2z)
\]
### Method 2: Grouping the terms differently
1. **Group the terms**: We can also group the terms in a different way. Let's factor out \( 3z \) from the second term:
\[
3xy + 6yz = 3xy + 3(2yz)
\]
2. **Factor out \( 3y \)**: Now we can factor out \( 3y \) from the entire expression:
\[
3y(x + 2z)
\]
### Summary of the two methods
1. From Method 1, we have:
\[
3y(x + 2z)
\]
2. From Method 2, we also arrive at:
\[
3y(x + 2z)
\]
Both methods yield the same factored form, but they illustrate different approaches to applying the distributive property.
Respondido por UpStudy AI y revisado por un tutor profesional
Como
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The Deep Dive
One way to rewrite \( 3xy + 6yz \) is by factoring out the common term \( 3y \): \[ 3y(x + 2z) \]. This showcases how both terms share a \( 3y \) factor, making it easy to identify that the expression can be simplified. Another approach is to group the terms differently by factoring out \( 3z \) when it applies: \[ 3y(x + 2z) \]. In this case, we can think of the expression in terms of \( z \) as well if it were adjusted to include a scenario where \( z \) is factored out, although it primarily highlights the first method.
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