\begin{tabular}{|l}\hline Question 7 \\ Identify the most simplified version of \\ the expression below: \\ \begin{tabular}{ll}\( -2 \sqrt{48}-3 \sqrt{48} \) \\ \( \begin{array}{ll}\text { A) }-20 \sqrt{3} & \text { B) }-44 \sqrt{3} \\ \text { C) }-32 \sqrt{3} & \text { D) }-52 \sqrt{3}\end{array} \) \\ OD \\ OB A \\ OC \\ \hline\end{tabular} \\ \hline\end{tabular}

Let's break this down with some quick calculations! First, we need to simplify \( -2 \sqrt{48} - 3 \sqrt{48} \). Combining the like terms gives us: \[ (-2 - 3) \sqrt{48} = -5 \sqrt{48} \] Now, we simplify \(\sqrt{48}\). Factoring gives us: \[ \sqrt{48} = \sqrt{16 \cdot 3} = 4\sqrt{3} \] Substituting back, we have: \[ -5 \sqrt{48} = -5 \cdot 4 \sqrt{3} = -20 \sqrt{3} \] So, the most simplified version of the expression is \( A) -20 \sqrt{3} \). Ready for some fun facts? Did you know that the square root of a number can often be simplified based on its prime factors? This makes it easier to handle radical expressions. When you break it down using factorization, such as identifying perfect squares, the process becomes much smoother! For real-world applications, learning to simplify expressions like this can be a game-changer in fields like engineering and architecture, where you often work with root calculations and need to present them in their simplest form for clear communication. Whether it’s calculating areas or designing structures, a clean solution helps avoid confusion!