Pregunta
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Factor completely. Then select the correct factors from the options below. (You will select two factors). \( 4 x^{2}-5 x-6 \)

Ask by Simmons Mills. in the United States
Feb 24,2025

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The factors are (4x + 3) and (x – 2).

Solución

We start with the quadratic:   4x² – 5x – 6 To factor, we look for two numbers that multiply to (a × c) = 4 × (–6) = –24 and add to b = –5. The numbers –8 and 3 work since (–8) + 3 = –5 and (–8) × 3 = –24. Now, rewrite the middle term using these numbers:   4x² – 8x + 3x – 6 Next, group the terms:   (4x² – 8x) + (3x – 6) Factor each group separately:   4x² – 8x = 4x(x – 2)   3x – 6 = 3(x – 2) Now, factor out the common binomial (x – 2):   = (x – 2)(4x + 3) Thus, the completely factored form is:   (4x + 3)(x – 2) So, the two factors you should select are: (4x + 3) and (x – 2).

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Mind Expander

To factor the quadratic \( 4x^2 - 5x - 6 \) completely, we first look for two numbers that multiply to \( 4 \times -6 = -24 \) and add up to \( -5 \). These numbers are \( -8 \) and \( 3 \). We can rewrite the equation as \( 4x^2 - 8x + 3x - 6 \), then group it as \( 4x(x - 2) + 3(x - 2) \), leading us to factor it as \( (4x + 3)(x - 2) \). Now, if you're picking factors, you would select \( (4x + 3) \) and \( (x - 2) \). This means that you effectively turned a puzzle into a masterpiece! Quadratics like this can often feel daunting, but once you break them down into manageable pieces, they become a lot easier to digest. Factorization is like unraveling a mystery — every equation holds its secrets waiting to be revealed! If you love diving into more advanced realms of algebra, consider tackling polynomials of higher degree or even exploring complex numbers. You'll soon find that the world of mathematics is filled with opportunities for discovery, and every new concept you master opens up a treasure trove of future challenges!

preguntas relacionadas

phrase I. The difference between three times \( x \) and fifteen is greater than or equal to five 2. Five more than sixteen times \( x \) is less than or equal to six 3. Three more than two times \( x \) is less than seven \( \square \) 4. Five less than four times \( x \) is less than or equal to sixteen 5. Six times the sum of \( x \) and twelve is less than fourteen 6. The difference between fifteen and two times \( x \) is greater than five 7. The difference between eleven and four times \( x \) is greater than or equal to three 8. The sum of negative three times \( x \) and five is less than or equal to negative four 9. Fourteen less than five times \( x \) is at most eleven \( \qquad \) 10. Twice the sum of nine and \( x \) is greater than twenty II. Ten less than three times \( x \) is greater than eleven 12. Thirteen plus five times \( x \) is no more than thirty 13. Thirteen more than three times \( x \) is no more than the opposite of eleven 14. Half of the sum of \( x \) and six is no less than twenty 15. The difference between negative five times \( x \) and eight is greater than twelve. Solve only your inequalities! Look for your answer at the bottom. \[ \begin{array}{ll} N \quad 2 x+3 \leq 7 & E \\ C & 14-5 x \leq 11 \\ \text { C } 15-2 x>5 & \text { R } \\ F(9+x)>20 \\ E \quad 1 / 2 x+6 x \leq 30 & \text { D } \end{array} 6(x+12)<141 \] \[ \text { L } 5 x-14 \leq 11 \quad H \quad-3 x-5<-4 \] \[ \text { U } 3 x-15 \geq 5 \quad \text { A } 1 / 2(x+6) \geq 20 \] \[ E \quad 6(x-12)>14 \backslash \text { H } \quad 11-4 x \geq 3 \] \[ 3 x-10>11 \quad 0 \quad-5 x-8>12 \] \[ \vee 16 x+5<6 \quad \& \quad 3 x+13 \leq-11 \] \[ \text { Y } 4 x-5 \geq 16 \quad \text { \& } 16 x+5 \leq 6 \]
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