Solve the equation: $$ (x+3)^{2}+5(x+3)-6=0 $$

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Solve the equation $$ (x+3)^{2}+5(x+3)-6=0 $$.
Solve the quadratic equation by following steps:
- step0: Solve by factoring:
  $$\left(x+3ight)^{2}+5\left(x+3ight)-6=0$$
- step1: Expand the expression:
  $$x^{2}+11x+18=0$$
- step2: Factor the expression:
  $$\left(x+2ight)\left(x+9ight)=0$$
- step3: Separate into possible cases:
  $$\begin{align}&x+2=0\&x+9=0\end{align}$$
- step4: Solve the equation:
  $$\begin{align}&x=-2\&x=-9\end{align}$$
- step5: Rewrite:
  $$x_{1}=-9,x_{2}=-2$$
The solutions to the equation $$ (x+3)^{2}+5(x+3)-6=0 $$ are $$ x=-9 $$ and $$ x=-2 $$.
The solutions are $$ x=-9 $$ and $$ x=-2 $$.

Solve the equation: \( (x+3)^{2}+5(x+3)-6=0 \)

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