Let \( f(x)=-8 x+3 \). Find \( f\left(\frac{1}{2}\right) \) \( f\left(\frac{1}{2}\right)=\square \) (Simplify your answer.)

To find \( f\left(\frac{1}{2}\right) \), we substitute \( \frac{1}{2} \) into the function \( f(x) = -8x + 3 \): \[ f\left(\frac{1}{2}\right) = -8\left(\frac{1}{2}\right) + 3 \] Calculating \( -8 \times \frac{1}{2} \): \[ -8 \times \frac{1}{2} = -4 \] Now, substituting back into the function: \[ f\left(\frac{1}{2}\right) = -4 + 3 = -1 \] So, \[ f\left(\frac{1}{2}\right) = -1 \]