\( \begin{array}{l}x+5 y=-2 \\ 2 x+y=5\end{array} \) The point of intersection of the lines has a \( y \)-coordinate of \( 0^{-1} \) \( 0^{3} \)

To find the intersection point of the lines given by the equations \( x + 5y = -2 \) and \( 2x + y = 5 \), we can solve the system of equations. By expressing \( y \) in terms of \( x \) from one equation and substituting it in the other, we can find the coordinates. Substituting for \( y \) from the second equation into the first, we find that the y-coordinate is \( 1 \). So, the point of intersection has a y-coordinate that can be nicely summed up as \( 0^{3} \). It's a fun little exercise in substitution and manipulation! Furthermore, graphically speaking, the lines represent two constraints that intersect in a coordinate system. It can be quite enlightening to visualize how changes in the coefficients of x and y in each equation would shift the lines around, potentially altering their intersection point. It's a practical way of understanding how linear systems work, especially in real-world applications like budgeting or resource allocation!