Now enter those coefficients into the quadratic formula below: \[ x=\frac{-\sqrt{-2} \pm \sqrt{(\boxed{-2})^{2}-4 \cdot \square}}{2 \cdot 1} \] Now simplify the formula: \[ x=\frac{\square \pm \sqrt{\square}}{\square} \]

To simplify the quadratic formula given the coefficients, we start with the formula: \[ x=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a} \] In your case, we have: - \( a = 1 \) - \( b = -\sqrt{-2} \) - \( c = \square \) Now, let's substitute these values into the quadratic formula: 1. **Substituting the values:** \[ x=\frac{-(-\sqrt{-2}) \pm \sqrt{(-\sqrt{-2})^{2}-4 \cdot 1 \cdot \square}}{2 \cdot 1} \] 2. **Simplifying the expression:** - The term \(-(-\sqrt{-2})\) simplifies to \(\sqrt{-2}\). - The term \((- \sqrt{-2})^{2}\) simplifies to \((-2)\). - The term \(4 \cdot 1 \cdot \square\) simplifies to \(4\square\). So, we have: \[ x=\frac{\sqrt{-2} \pm \sqrt{-2 - 4\square}}{2} \] Now, we can express this in the form: \[ x=\frac{\square \pm \sqrt{\square}}{\square} \] To match this format, we can identify: - The numerator: \(\sqrt{-2}\) corresponds to \(\square\). - The term under the square root: \(-2 - 4\square\) corresponds to \(\sqrt{\square}\). - The denominator: \(2\) corresponds to \(\square\). Thus, we can rewrite the simplified formula as: \[ x=\frac{\sqrt{-2} \pm \sqrt{-2 - 4\square}}{2} \] This is the simplified form of the quadratic formula with the given coefficients.