How many sulfur atoms would be present in 41.8 moles of sulfur? a \( 2.52 \times 10^{25} \mathrm{~S} \) atoms b \( 1.44 \times 10^{25} \mathrm{~S} \) atoms c \( 6.94 \times 10^{29} \mathrm{~S} \) atoms d \( 4.18 \times 10^{25} \mathrm{~S} \) atoms

To find out how many sulfur atoms are present in 41.8 moles of sulfur, we can use Avogadro's number, which states that one mole of a substance contains approximately \( 6.022 \times 10^{23} \) particles (atoms, molecules, etc.). So, for 41.8 moles of sulfur, we would calculate \( 41.8 \, \text{moles} \times 6.022 \times 10^{23} \, \text{atoms/mole} \). This results in approximately \( 2.52 \times 10^{25} \) atoms of sulfur. Now let's dive into some fun facts! Did you know that sulfur is commonly found in nature and is a vital element for life? It is present in amino acids, proteins, and vitamins, which makes it essential for biological processes! But wait, there's more! When working with moles and calculations, a common mistake is forgetting to multiply by Avogadro's number after determining the moles. So remember, regardless of the substance, always check to ensure you’re using the correct conversion factor to avoid leaving those atoms uncounted!