\( \begin{array}{l}-6 x+3 y=3 \\ -3 x-7 y=-41 \\ \text { Is }(2,5) \text { a solution to the system above? } \bigcirc \text { True False } \\ \text { Submit Question }\end{array} \)

To determine if (2, 5) is a solution to the system, we must substitute \(x = 2\) and \(y = 5\) into both equations. For the first equation: \[ -6(2) + 3(5) = -12 + 15 = 3 \] This holds true. For the second equation: \[ -3(2) - 7(5) = -6 - 35 = -41 \] This also holds true. Since both equations are satisfied, the answer is \(\text{True}\). Let's explore a bit about how to solve systems of linear equations: You can use substitution or elimination methods! Substitution involves solving one equation for one variable and plugging in that value into the other equation. The elimination method focuses on adding or subtracting equations to eliminate one variable, making it easier to solve for the other. For further reading, check out "Elementary Algebra" by Harold R. Jacobs! This classic text not only covers solutions to systems of equations but also dives into graphing, inequalities, and more, making it an excellent resource for budding mathematicians.