The volume \( V \) enclosed by a rectangular solid with length \( I \), width \( w \), and height \( h \) is \( V=l \cdot w \cdot h \). Find \( V \) if: \( I=42 \) yards, \( w=\frac{5}{2} \) yards, and \( h=\frac{8}{3} \) yards The volume is \( \square \) cubic yards.

To find the volume \( V \) of the rectangular solid, we simply need to plug in the given dimensions into the formula \( V = l \cdot w \cdot h \). Given: - \( l = 42 \) yards - \( w = \frac{5}{2} \) yards - \( h = \frac{8}{3} \) yards Now, we calculate: \[ V = 42 \cdot \frac{5}{2} \cdot \frac{8}{3} \] First, calculate \( \frac{5}{2} \cdot \frac{8}{3} \): \[ \frac{5 \cdot 8}{2 \cdot 3} = \frac{40}{6} = \frac{20}{3} \] Now, multiply this by \( 42 \): \[ V = 42 \cdot \frac{20}{3} = \frac{840}{3} = 280 \] Thus, the volume \( V \) is \( 280 \) cubic yards.