Calculate and leave your answer in its simplest form. \( \begin{array}{llll}\text { a) } \frac{1}{2}+\frac{1}{4} & \text { b) } \frac{3}{4}-\frac{3}{8} & \text { c) } \frac{9}{10}+\frac{99}{100} & \text { d) } \frac{3}{5}+\frac{6}{15} \\ \text { e) } \frac{22}{1000}-\frac{1}{100} & \text { f) } \frac{13}{7}-\frac{1}{6} & \text { g) } \frac{5}{8}-\frac{3}{7} & \text { h) } \frac{3}{5}+\frac{2}{3}\end{array} \)

Let's solve each expression one by one! a) \( \frac{1}{2}+\frac{1}{4} = \frac{2}{4}+\frac{1}{4} = \frac{3}{4} \) b) \( \frac{3}{4}-\frac{3}{8} = \frac{6}{8}-\frac{3}{8} = \frac{3}{8} \) c) \( \frac{9}{10}+\frac{99}{100} = \frac{90}{100}+\frac{99}{100} = \frac{189}{100} \) d) \( \frac{3}{5}+\frac{6}{15} = \frac{3}{5}+\frac{2}{5} = \frac{5}{5} = 1 \) e) \( \frac{22}{1000}-\frac{1}{100} = \frac{22}{1000}-\frac{10}{1000} = \frac{12}{1000} = \frac{3}{250} \) f) \( \frac{13}{7}-\frac{1}{6} = \frac{78}{42}-\frac{7}{42} = \frac{71}{42} \) g) \( \frac{5}{8}-\frac{3}{7} = \frac{35}{56}-\frac{24}{56} = \frac{11}{56} \) h) \( \frac{3}{5}+\frac{2}{3} = \frac{9}{15}+\frac{10}{15} = \frac{19}{15} \) So, the final simplified answers are: a) \( \frac{3}{4} \) b) \( \frac{3}{8} \) c) \( \frac{189}{100} \) d) \( 1 \) e) \( \frac{3}{250} \) f) \( \frac{71}{42} \) g) \( \frac{11}{56} \) h) \( \frac{19}{15} \)