Compute each of the absolute values. (a) \( |4-5| \) (b) \( |(-6)-(-3)| \) (c) \( |6-(-7)| \) (d) \( |(-3)-4| \) (a) \( |4-5|=1 \) (b) \( |(-6)-(-3)|=\square \)

To solve (b): \( |(-6)-(-3)| \) simplifies to \( | -6 + 3 | = | -3 | = 3 \). Now for the others: (c) \( |6-(-7)| \) can be rewritten as \( |6 + 7| = |13| = 13 \). (d) \( |(-3)-4| \) turns into \( |-3 - 4| = |-7| = 7 \). So, the answers are: (a) \( |4-5| = 1 \) (b) \( |(-6)-(-3)| = 3 \) (c) \( |6-(-7)| = 13 \) (d) \( |(-3)-4| = 7 \)