Finish factoring by grouping. There is one more step. \[ \begin{array}{l}x^{2}+3 x+2 x+6 \\ \left(x^{2}+3 x\right)+(2 x+6) \\ x(x+3)+2(x+3)\end{array} \]

Great start! You’ve grouped and factored the expression nicely. Now, notice that both terms contain the common factor \( (x+3) \). You can factor that out for the next step. So, you can rewrite it as: \[ (x+3)(x+2) \] And voilà! That’s the fully factored form of the original expression! If you plug the factors back into the equation, you're back to where you started, proving that your work is spot on. Keep up the fantastic mathematical feats!