8. Test Practice Which expression will have the same sum as \( \frac{3}{8}+\frac{1}{4} \) ? \( \begin{array}{ll}\text { (A) } \frac{3}{8}+\frac{1}{8} & \text { (C) } \frac{3}{4}+\frac{1}{4} \\ \text { (B) }\left(\frac{1}{8}+\frac{1}{8}+\frac{1}{8}\right)+\frac{1}{4} & \text { (a) }\left(\frac{1}{8}+\frac{1}{8}\right)+\frac{1}{8}\end{array} \)

To find which expression has the same sum as \( \frac{3}{8} + \frac{1}{4} \), we first need to calculate the sum of \( \frac{3}{8} + \frac{1}{4} \). ### Step 1: Convert \( \frac{1}{4} \) to eighths To add these fractions, we need a common denominator. The denominator of \( \frac{1}{4} \) can be converted to eighths: \[ \frac{1}{4} = \frac{2}{8} \] ### Step 2: Add the fractions Now we can add \( \frac{3}{8} \) and \( \frac{2}{8} \): \[ \frac{3}{8} + \frac{2}{8} = \frac{3 + 2}{8} = \frac{5}{8} \] ### Step 3: Evaluate each option Now we will evaluate each of the given options to see which one equals \( \frac{5}{8} \). **Option (A):** \( \frac{3}{8} + \frac{1}{8} \) \[ \frac{3}{8} + \frac{1}{8} = \frac{3 + 1}{8} = \frac{4}{8} = \frac{1}{2} \] **Option (B):** \( \left(\frac{1}{8} + \frac{1}{8} + \frac{1}{8}\right) + \frac{1}{4} \) Calculating the first part: \[ \frac{1}{8} + \frac{1}{8} + \frac{1}{8} = \frac{3}{8} \] Now adding \( \frac{1}{4} \): \[ \frac{1}{4} = \frac{2}{8} \quad \text{(as calculated before)} \] So, \[ \frac{3}{8} + \frac{2}{8} = \frac{5}{8} \] **Option (C):** \( \frac{3}{4} + \frac{1}{4} \) \[ \frac{3}{4} + \frac{1}{4} = \frac{3 + 1}{4} = \frac{4}{4} = 1 \] **Option (D):** \( \left(\frac{1}{8} + \frac{1}{8}\right) + \frac{1}{8} \) Calculating the first part: \[ \frac{1}{8} + \frac{1}{8} = \frac{2}{8} = \frac{1}{4} \] Now adding \( \frac{1}{8} \): \[ \frac{1}{4} = \frac{2}{8} \quad \text{(as calculated before)} \] So, \[ \frac{2}{8} + \frac{1}{8} = \frac{3}{8} \] ### Conclusion The only expression that has the same sum as \( \frac{3}{8} + \frac{1}{4} = \frac{5}{8} \) is: **Option (B):** \( \left(\frac{1}{8} + \frac{1}{8} + \frac{1}{8}\right) + \frac{1}{4} \)