Pregunta
13. A salesman travelled 450 km in a day: one-third of the distance before lunch and two-fifths between lunch and tea. The rest was after tea. Write a ratio for the distance travelled before lunch: between lunch and tea: after to
Ask by Gibbs Barker. in New Zealand
Feb 27,2025
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The ratio of distances is 5:6:4 before lunch, between lunch and tea, and after tea.
Solución
The salesman traveled 450 km in total.
Distance before lunch = 1/3 of 450 = 150 km.
Distance between lunch and tea = 2/5 of 450 = 180 km.
Distance after tea = 450 - (150 + 180) = 120 km.
The ratio is therefore 150 : 180 : 120. Simplifying by dividing each term by 30 gives 5 : 6 : 4.
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Simplifique esta solución Extra Insights
Before lunch, the salesman traveled one-third of 450 km, which is 150 km. Between lunch and tea, he covered two-fifths of the total distance, equating to 180 km. Thus, the remaining distance after tea is 450 km - (150 km + 180 km) = 120 km. The ratio for the distances traveled can be expressed as 150 km: 180 km: 120 km, which simplifies to 5:6:4. To simplify this further, you can divide each part of the ratio by 30: (150 ÷ 30):(180 ÷ 30):(120 ÷ 30) = 5:6:4. This is a neat illustration of how fractions can be used to break down larger numbers into more manageable pieces, making math not only accessible but also a little more fun!
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