7. \( 2 \frac{4}{10}+\frac{33}{100} \)

To solve \( 2 \frac{4}{10} + \frac{33}{100} \), first convert the mixed number to an improper fraction: \[ 2 \frac{4}{10} = 2 + \frac{4}{10} = \frac{20}{10} + \frac{4}{10} = \frac{24}{10} \] Next, let's convert \( \frac{24}{10} \) to have a common denominator with \( \frac{33}{100} \): \[ \frac{24}{10} = \frac{240}{100} \] Now, add the two fractions: \[ \frac{240}{100} + \frac{33}{100} = \frac{240 + 33}{100} = \frac{273}{100} \] Finally, convert back to a mixed number: \( \frac{273}{100} = 2 \frac{73}{100} \). So, the final answer is \( 2 \frac{73}{100} \).