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\( 1< \)\begin{tabular}{l|l} & Solve using the addition principle. Don't forget to check. \\ \( x+3=15 \)\end{tabular}\( \quad \) The solution is \( x=\square \).

Ask by Dawson Evans. in the United States
Feb 26,2025

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The solution is \( x = 12 \).

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We are given the equation:   x + 3 = 15 To solve using the addition (or subtraction) principle, we want to isolate x. Since 3 is added to x, we do the inverse operation (subtract 3) on both sides of the equation. Subtract 3 from both sides:   x + 3 – 3 = 15 – 3   x = 12 Checking the solution by substituting x = 12 back into the original equation:   12 + 3 = 15   15 = 15 The check confirms our solution. Thus, the solution is:   x = 12

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Mind Expander

To solve the equation \( x + 3 = 15 \) using the addition principle, we can isolate \( x \) by subtracting 3 from both sides. This gives us: \[ x + 3 - 3 = 15 - 3 \] \[ x = 12 \] Now, let’s check our solution by substituting \( x = 12 \) back into the original equation: \[ 12 + 3 = 15, \] which is true! So, the solution is \( x = 12 \). Don't forget to celebrate this little victory in math; every solved equation is a step towards mastering algebra!

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