Pregunta
Analyze the effect on the domain and range of \( f(x)=\ln (x) \) when \( f(x) \) is replaced by \( a f(x) \) where \( a<0 \). Option \#1: Neither the domain nor the range change. Option \#2: The domain changes, but the range does not. Option \#3: The range changes, but the domain does not. Option \#4: Both the domain and the range change. (1 point) Option \# describes the effect on the domain and range of \( f(x)=\ln (x) \) when \( f(x) \) is replaced
Ask by Schmidt Watkins. in the United States
Feb 26,2025
Solución de inteligencia artificial de Upstudy
Respuesta verificada por el tutor
Responder
Neither the domain nor the range of \( f(x) = \ln(x) \) changes when multiplied by a negative constant \( a \).
Solución
The function f(x) = ln(x) has a domain of (0, ∞) and a range of (–∞, ∞).
When you multiply by a constant a where a < 0, the operation becomes g(x) = a·ln(x). Multiplying by a constant does not affect the x-values for which ln(x) is defined. Therefore, the domain remains (0, ∞).
Since ln(x) can take any real value, multiplying by any nonzero constant (even a negative one) will still produce all real numbers (although the output will be "stretched" and reflected). Thus, the range remains (–∞, ∞).
So, the correct option is Option #1: Neither the domain nor the range change.
Respondido por UpStudy AI y revisado por un tutor profesional
Como
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Extra Insights
The correct option is Option #3: The range changes, but the domain does not. Here's why: The domain of \( f(x) = \ln(x) \) is \( x > 0 \), which remains unchanged even when \( f(x) \) is replaced by \( a f(x) \) where \( a < 0 \). However, the range of \( f(x) \) is all real numbers, but when \( a < 0 \), the range is inverted to all negative real numbers. Thus, the effect is that while the domain stays the same, the negative multiplier alters the range.
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