Solve for the unknown number in the following expressions. a. \( y \div 3=4 R 2 \) b. \( 33 \div x=4 R 5 \) a. \( y=\square \)

To solve for \( y \) in the expression \( y \div 3 = 4 R 2 \), we first interpret \( 4 R 2 \) as 4 with a remainder of 2. This means that when we divide \( y \) by 3, we get 4 as a quotient, and the leftover is 2. Therefore, we can write this as: \[ y = 3 \times 4 + 2 \] \[ y = 12 + 2 \] \[ y = 14 \] So, \( y = 14 \). Now, for \( x \) in \( 33 \div x = 4 R 5 \), we see that 4 R 5 means when we divide 33 by \( x \), we get a quotient of 4 and a remainder of 5. We can express that mathematically as: \[ 33 = 4x + 5 \] Subtracting 5 from both sides, we have: \[ 28 = 4x \] Now dividing both sides by 4 gives us: \[ x = 7 \] So, the solutions are: a. \( y = 14 \) b. \( x = 7 \)