27.Q A particle moves from rest in a straight line with uniform acceleration. it covered 24 m . in the first four seconds of starting its motion, then the magnitude of its acceleration \( =\ldots \ldots \ldots . . \). m.sec.
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To find the magnitude of the acceleration, we can use the equation of motion: \[ s = ut + \frac{1}{2} a t^2 \] Since the particle starts from rest, \( u = 0 \), and the equation simplifies to: \[ s = \frac{1}{2} a t^2 \] Plugging in the values: \[ 24 = \frac{1}{2} a (4)^2 \] \[ 24 = \frac{1}{2} a \cdot 16 \] \[ 24 = 8a \] \[ a = \frac{24}{8} = 3 \, \text{m/sec}^2 \] So, the magnitude of the acceleration is \( 3 \, \text{m/sec}^2 \).
