Subtract the polynomials. \( \begin{array}{l}\left(-3 r^{2}+3 r+7\right)-\left(7 r^{2}+5 r-2\right) \\ \left(-3 r^{2}+3 r+7\right)-\left(7 r^{2}+5 r-2\right)=\square \\ \text { (Simplify your answer. })\end{array} \)

To subtract the polynomials, distribute the negative sign across the second polynomial: \[ (-3r^2 + 3r + 7) - (7r^2 + 5r - 2) = -3r^2 + 3r + 7 - 7r^2 - 5r + 2 \] Now combine like terms: 1. For \(r^2\) terms: \(-3r^2 - 7r^2 = -10r^2\) 2. For \(r\) terms: \(3r - 5r = -2r\) 3. For the constant terms: \(7 + 2 = 9\) Putting it all together, the simplified result is: \[ -10r^2 - 2r + 9 \] So, the final expression is: \[ \boxed{-10r^2 - 2r + 9} \]