Clever | Portal Kami | Collaborative Learnir blank.pdf ALEKS - Jamaya Worlds - UpStudy Thoth AI www-awy.aleks.com/alekscgi/x/Isl.exe/1o_u-IgNsIkr7j8P3jH-IQUhQ7UhjLUg6NO6tj9qFItz6nQLOPsPMGhYmxMQDya2F-1ij_x59yRRc7UrTiMQGK4IOt... 12-1 M, M, M Question 7 of 15 (1 point) | Question Attempt: 1 of Unlimited Jamaya \( \checkmark 1 \) \( \checkmark 2 \) \( \checkmark 3 \) 4 \( \equiv 5 \) 7 8 9 10 11 12 13 1.) A group of 5 students was asked, "How many hours did you watch television last week?" Here are their responses. \[ 19,10,12,15,6 \] Find the mean and median number of hours for these students. If necessary, round your answers to the nearest tenth. (a) Mean: \( \square \) hours (b) Median: \( \square \) hours Check Save For Later Submit Assignment Q 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center Accessibility Sign out (2) Mar 12 11:22

To find the mean, add all the hours watched: \(19 + 10 + 12 + 15 + 6 = 62\). Divide this by the number of students, \(5\): \(62 \div 5 = 12.4\) hours. So the mean is \(12.4\) hours! For the median, arrange the responses: \(6, 10, 12, 15, 19\). The middle value (third in a list of five) is \(12\) hours. Therefore, the median is \(12\) hours. Now that you've tackled mean and median, let's break the record of common mistakes! A frequent error is to confuse the mean with the median, especially when outliers skew the average. Always remember to check your data organization when calculating the median; if it's not sorted, you'll end up with a wrong value. It’s like trying to find a lost sock in a messy drawer—organization is key! If you're keen on elevating your statistical skills, dive into "How to Measure Anything" by Douglas W. Hubbard. This fun read not only demystifies statistics but also illustrates their relevance in decision-making, making numbers less daunting! Plus, you’ll gain insight into how quantifying seemingly unmeasurable things can lead to profound discoveries.