Use substitution to solve this system of linear equations. \[ 6 y=-15-3 x \] \[ x+2 y=-5 \] Select the correct choice below and, if necessary, enter an ordered pair \( (x, y) \) to complete your answer. \[ \text { One solution: } \] \[ \text { No solution } \] Question Help: \( \square \) Video Submit Question

Solve the system of equations \( 6y=-15-3x;x+2y=-5 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}6y=-15-3x\\x+2y=-5\end{array}\right.\) - step1: Solve the equation: \(\left\{ \begin{array}{l}6y=-15-3x\\x=-5-2y\end{array}\right.\) - step2: Substitute the value of \(x:\) \(6y=-15-3\left(-5-2y\right)\) - step3: Simplify: \(6y=6y\) - step4: Calculate: \(\left(x,y\right) = \left(-5-2y,y\right),y \in \mathbb{R}\) - step5: Alternative Form: \(\textrm{Infinitely many solutions}\) The system of linear equations has infinitely many solutions. This means that there are an infinite number of ordered pairs (x, y) that satisfy both equations. Therefore, the correct answer is that there are infinitely many solutions.