Pregunta
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A \( -75 x+57=-75 x+57 \) B \( 75 x+57=-75 x+57 \) C \( -57 x+57=-75 x+75 \) D \( 57 x+57=-75 x-75 \)

Ask by Klein Ortiz. in the United States
Feb 27,2025

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Option A is always true for any value of \(x\). Options B, C, and D have specific solutions: \(x = 0\), \(x = 1\), and \(x = -1\) respectively.

Solución

Let's analyze the equations provided in options A, B, C, and D. We will solve each equation step by step. ### Option A: \[ -75x + 57 = -75x + 57 \] This equation simplifies to \(0 = 0\), which is always true. Therefore, this equation is valid for all values of \(x\). ### Option B: \[ 75x + 57 = -75x + 57 \] To solve for \(x\), we can first subtract \(57\) from both sides: \[ 75x = -75x \] Now, add \(75x\) to both sides: \[ 75x + 75x = 0 \implies 150x = 0 \] Dividing both sides by \(150\): \[ x = 0 \] ### Option C: \[ -57x + 57 = -75x + 75 \] First, let's add \(75x\) to both sides: \[ -57x + 75x + 57 = 75 \] This simplifies to: \[ 18x + 57 = 75 \] Now, subtract \(57\) from both sides: \[ 18x = 18 \] Dividing both sides by \(18\): \[ x = 1 \] ### Option D: \[ 57x + 57 = -75x - 75 \] First, add \(75x\) to both sides: \[ 57x + 75x + 57 = -75 \] This simplifies to: \[ 132x + 57 = -75 \] Now, subtract \(57\) from both sides: \[ 132x = -132 \] Dividing both sides by \(132\): \[ x = -1 \] ### Summary of Solutions: - **Option A**: Valid for all \(x\) - **Option B**: \(x = 0\) - **Option C**: \(x = 1\) - **Option D**: \(x = -1\) If you need further analysis or specific information about any of these equations, please let me know!

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Bonus Knowledge

Solving equations can often resemble a puzzle, where you need to isolate the variable. For instance, in the equation A, both sides are identical, meaning any value of \( x \) is a solution. This is a fun reminder that sometimes, the simplest answer is the best—no math gymnastics required! On the other hand, with equation B, you'll notice we can combine like terms. When you move all the \( x \) terms to one side, you find the need to carefully check your steps, especially regarding signs. It's a common mistake to forget that moving terms across the equals sign changes their signs—so watch out for that!

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