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When \( y = -1 \), the expression \( y^{3}+3y^{2}-y+5 \) equals 8.
Solución
Substitute \( y=-1 \) into the expression \( y^{3}+3y^{2}-y+5 \).
Evaluate the expression by following steps:
- step0: Evaluate:
\(y^{3}+3y^{2}-y+5\)
- step1: Substitute:
\(\left(-1\right)^{3}+3\left(-1\right)^{2}-\left(-1\right)+5\)
- step2: Evaluate the power:
\(\left(-1\right)^{3}+3\times 1-\left(-1\right)+5\)
- step3: Multiply:
\(\left(-1\right)^{3}+3-\left(-1\right)+5\)
- step4: Evaluate the power:
\(-1+3-\left(-1\right)+5\)
- step5: Subtract the numbers:
\(2-\left(-1\right)+5\)
- step6: Subtract the terms:
\(3+5\)
- step7: Add the numbers:
\(8\)
When \( y = -1 \), the expression \( y^{3}+3y^{2}-y+5 \) evaluates to 8.
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Simplifique esta solución Extra Insights
When you substitute \( y = -1 \) into the expression \( y^3 + 3y^2 - y + 5 \), it’s like taking a little rollercoaster ride through numbers! So, let's plug it in: \[ (-1)^3 + 3(-1)^2 - (-1) + 5 \] This simplifies to: \[ -1 + 3(1) + 1 + 5 \] Calculating this step-by-step gives you: \[ -1 + 3 + 1 + 5 = 8 \] The expression evaluates to 8 when \( y = -1 \). Isn’t math magical?
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