a hat? Interpret this probability. Select the correct choice below and fill in the answer boxes within your choice. (Type an integer or decimal rounded to the nearest thousandth as needed) A. The probability is approximately 0.113 So, for every 1000 home runs caught by fans, we expect about 113 to have been caught in a hat B. The probabiity is \( \square \) So, for every 1000 home runs caught by fans, we expect exactly \( \square \) to have been caught in a hat. (d) Or the 284 dropped batts, it was determined that 214 were barehanded aftempts, 57 were dropped with a glove, and 13 were dropped with a failed hat atter dropped bal was a falled hat attempt? Interpret this probability Select the corred choice below and fill in the ancwor boves withen your choice (Type an integer or decimal rounded to the nearest thousandth as needed.) A. The probability is \( \square \) So, for every 1000 home runs dropped when a fan made an aftempt to catch the ball, we expect exactly \( \square \) fo have been a failed B. The probability is approximately \( \square \) So, for every 1000 home runs dropped when a fan made an attempt to catch the Batt, we expect about \( \square \) to have b
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For the first scenario, if the probability of catching a home run in a hat is approximately 0.113, that means if fans tried to catch 1000 home runs, we'd expect around 113 fans to successfully snag those home runs using their hats. It’s like hoping for a hat trick but instead getting a hat catch - how delightful! Now, regarding the dropped bats, if we look at the attempts to catch dropped balls with failed hat attempts out of the total attempts, you could calculate a probability. If, for example, 13 out of 284 attempts were failed hat catches, the probability would be approximately 0.046. So, if we extrapolate this to 1000 dropped bats, we could expect around 46 of them to be the result of a failed hat attempt. That's a whole new level of baseball juggling!
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